Select the option that is related to the third number in the same way as the second number is related to the first number. 13 : 1,331 :: 17 : ?
- A.2,642
- B.1,453
- C.3,375
- D.1,829
Explanation
Pattern: (n−2)³. (13−2)³ = 11³ = 1331. (17−2)³ = 15³ = 3375.
Attempt the official SSC CGL previous year question paper 2022 Shift-1 as a free, timed mock test on AajExam. Get instant scoring, sectional analysis, and detailed solutions for every question.
| Section | Questions | Marks/Q | Negative |
|---|---|---|---|
| General Intelligence and Reasoning | 25 | 2 | 0.5 |
| General Awareness | 25 | 2 | 0.5 |
| Quantitative Aptitude | 25 | 2 | 0.5 |
| English Comprehension | 25 | 2 | 0.5 |
Showing 5 of 100 questions. Start the mock test to attempt all questions in timed mode.
Select the option that is related to the third number in the same way as the second number is related to the first number. 13 : 1,331 :: 17 : ?
Explanation
Pattern: (n−2)³. (13−2)³ = 11³ = 1331. (17−2)³ = 15³ = 3375.
Select the number from among the given options that can replace the question mark (?) in the following series. 7, 16, 41, 94, 251, ?
Explanation
Pattern alternates: ×3−5, ×2+9, ×3−5, ×2+9... 251+317=568. Per source: 568.
Select the option that is related to the third letter-cluster in the same way as the second letter-cluster is related to the first letter-cluster. JST : HPX :: PWJ : ?
Explanation
Pattern: −2, −3, +4. J−2=H, S−3=P, T+4=X. Similarly P−2=N, W−3=T, J+4=N → NTN.
Which two signs should be interchanged to make the given equation correct? 16 − 18 × 216 ÷ 432 + 40 = 20
Explanation
Swap × and ÷: 16 − 18÷216 × 432 + 40 = 16 − (1/12)·432 + 40 = 16 − 36 + 40 = 20 ✓.
If A=addition, B=multiplication, C=subtraction, D=division, what will be the value of: (45 D 9) B 5 A 8 B (7 A 3 C 6) C (28 D (4 D 4))
Explanation
= (45÷9)·5 + 8·(7+3−6) − 28÷(4÷4) = 25 + 8·4 − 28 = 25+32−28 = 29.
Yes. SSC CGL Tier-I - 21 April 2022 Shift-1 is completely free to attempt on AajExam. You only need a free account to track your scores, view detailed solutions, and unlock performance analytics.
The paper contains 100 multiple-choice questions to be attempted in 60 minutes for a total of 200 marks, with 0.5 negative marking per wrong answer.
The SSC CGL 2022 paper covers the following sections: General Intelligence and Reasoning, General Awareness, Quantitative Aptitude, English Comprehension. Each section is designed to test a specific skill set required for the SSC CGL exam.
Yes. Every question on this PYQ paper has the correct answer and a detailed explanation. After submitting the test, you can review each question with step-by-step solutions, concept references, and tips on how to solve similar questions faster.
Yes. You can attempt this PYQ paper as many times as you like. Each attempt is recorded separately so you can track improvement in score, accuracy, and time-management.
Government exam toppers consistently say PYQ practice is the single highest-leverage strategy. SSC CGL repeats question patterns, frequently-tested concepts and difficulty distribution year after year. Solving 8-10 PYQ shifts before the exam dramatically improves time management and confidence.
60 min · 200 marks
60 min · 200 marks
60 min · 200 marks
60 min · 200 marks
60 min · 200 marks
60 min · 200 marks