The sides (in cm) of a right triangle are (x − 13), (x − 26) and x. Its area (in cm²) is:
- A.999
- B.1014
- C.1010
- D.1012
Explanation
Hypotenuse x; legs (x−13), (x−26). x² = (x−13)² + (x−26)² → 0 = x² − 78x + 845 → x = 65. Area = (52 × 39)/2 = 1014.
Attempt the official RRB NTPC previous year question paper 2025 Shift-1 as a free, timed mock test on AajExam. Get instant scoring, sectional analysis, and detailed solutions for every question.
| Section | Questions | Marks/Q | Negative |
|---|---|---|---|
| Mathematics | 30 | 1 | 0.33 |
| General Intelligence & Reasoning | 30 | 1 | 0.33 |
| General Awareness | 40 | 1 | 0.33 |
Showing 5 of 100 questions. Start the mock test to attempt all questions in timed mode.
The sides (in cm) of a right triangle are (x − 13), (x − 26) and x. Its area (in cm²) is:
Explanation
Hypotenuse x; legs (x−13), (x−26). x² = (x−13)² + (x−26)² → 0 = x² − 78x + 845 → x = 65. Area = (52 × 39)/2 = 1014.
If tan θ = 7/8, then evaluate (1 − sin θ)(1 + sin θ) / [(1 + cos θ)(1 − cos θ) cot θ]
Explanation
= (1 − sin²θ)/[(1 − cos²θ) × cot θ] = cos²θ/[sin²θ × cot θ] = cos²θ/[cos θ × sin θ] = cot θ × ... = tan θ = 7/8? Per the official key option 1 = 8/7.
If 24 is subtracted from three times an unknown number, the difference is 258. What is the unknown number?
Explanation
3x − 24 = 258 → x = 282/3 = 94.
The sides of a rectangular field are 169 m and 154 m. Its area equals the area of a circular field. What is the circumference (in m) of the circular field? (π = 22/7)
Explanation
Area = 169 × 154 = πr² → r² = 169×154×7/22 = 169×49 → r = 91. Circumference = 2π×91 = 572 m.
Which of the following actors was honoured with the 2025 International Goya Award for his contributions to global cinema?
Explanation
Richard Gere received the 2025 International Goya Award for his contributions to global cinema.
Yes. RRB NTPC - 6 June 2025 Shift-1 is completely free to attempt on AajExam. You only need a free account to track your scores, view detailed solutions, and unlock performance analytics.
The paper contains 100 multiple-choice questions to be attempted in 90 minutes for a total of 100 marks, with 0.33 negative marking per wrong answer.
The RRB NTPC 2025 paper covers the following sections: Mathematics, General Intelligence & Reasoning, General Awareness. Each section is designed to test a specific skill set required for the RRB NTPC exam.
Yes. Every question on this PYQ paper has the correct answer and a detailed explanation. After submitting the test, you can review each question with step-by-step solutions, concept references, and tips on how to solve similar questions faster.
Yes. You can attempt this PYQ paper as many times as you like. Each attempt is recorded separately so you can track improvement in score, accuracy, and time-management.
Government exam toppers consistently say PYQ practice is the single highest-leverage strategy. RRB NTPC repeats question patterns, frequently-tested concepts and difficulty distribution year after year. Solving 8-10 PYQ shifts before the exam dramatically improves time management and confidence.
90 min · 100 marks
90 min · 100 marks
90 min · 100 marks
90 min · 100 marks
90 min · 100 marks
90 min · 100 marks