A carbon resistor of (47 ± 4.7) kW is to be marked with rings of different colours for its identification. The colour code sequence will be

- A.(A)
- B.(B)
- C.(C)
- D.(D)
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| Section | Questions | Marks/Q | Negative |
|---|---|---|---|
| Physics | 45 | 4 | 1 |
| Chemistry | 45 | 4 | 1 |
| Biology | 90 | 4 | 1 |
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A carbon resistor of (47 ± 4.7) kW is to be marked with rings of different colours for its identification. The colour code sequence will be

A set of ‘n’ equal resistors, of value ‘R’ each, are connected in series to a battery of emf ‘E’ and internal resistance ‘R’. The current drawn is I. Now, the ‘n’ resistors are connected in parallel to the same battery. Then the current drawn from battery becomes 10 I. The value of ‘n’ is

A battery consists of a variable number ‘n’ of identical cells (having internal resistance ‘r’ each) which are connected in series. The terminals of the battery are short-circuited and the current I is measured. Which of the graphs shows the correct relationship between I and n ?

The power radiated by a black body is P and it radiates maximum energy at wavelength, l₀. If the temperature of the black body is now changed so that it radiates maximum energy at wavelength 3 4 l₀, the power radiated by it becomes nP. The value of n is

Two wires are made of the same material and have the same volume. The first wire has cross-sectional area A and the second wire has cross-sectional area 3A. If the length of the first wire is increased by Dl on applying a force F, how much force is needed to stretch the second wire by the same amount ?

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The paper contains 180 multiple-choice questions to be attempted in 180 minutes for a total of 720 marks, with 1 negative marking per wrong answer.
The NEET 2018 paper covers the following sections: Physics, Chemistry, Biology. Each section is designed to test a specific skill set required for the NEET exam.
Yes. Every question on this PYQ paper has the correct answer and a detailed explanation. After submitting the test, you can review each question with step-by-step solutions, concept references, and tips on how to solve similar questions faster.
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