Previous year questions · SSC GD Constable

SSC GD Constable Elementary Mathematics — Previous Year Questions

450 Elementary Mathematics questions asked in past SSC GD Constable papers, split into 45 timed practice sets — every question with its answer and explanation.

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About SSC GD Constable Elementary Mathematics previous year questions

This page collects every Elementary Mathematics question that has appeared in past SSC GD Constable papers on AajExam — 450 questions in total, organised into 45 short, timed practice sets. Each question is shown with its four options, the correct answer, and an explanation of the reasoning, so you can use the page either as a self-test or as a revision reference. Why previous year questions are the highest-value Elementary Mathematics preparation you can do for SSC GD Constable: recruitment boards reuse a stable pool of concepts across cycles. The wording changes, the underlying idea rarely does. Working through a few hundred genuine past Elementary Mathematics questions teaches you which sub-topics the paper actually rewards, how the examiner likes to frame distractors, and roughly how long each question type should take — none of which a syllabus document can tell you. How to use this page: attempt questions in blocks of ten without looking at the answers, then review every question you got wrong or guessed. Read the explanation for the concept, not just the answer letter. When a concept keeps catching you out, open the related topic page linked below and drill that single area before returning here. Repeat across the full bank, and track how your accuracy on the second pass compares with your first — a 15-20% improvement is normal and is the clearest sign your preparation is working. What is in this bank: the questions are transcribed from actual SSC GD Constable question papers, kept in the original order and wording, with solutions written by subject specialists. Sets are free to attempt, work on mobile, and need no login to read. If you would rather practise a complete paper end to end under exam conditions, the full SSC GD Constable previous-year papers are linked below as well.

Elementary Mathematics PYQs asked in SSC GD Constable

A sample of 30 questions from the full bank of 450. Try each one before opening the solution — the remaining questions are in the timed practice sets below.

  1. Q1.A can complete 40% of a work in 6 days and B can complete 33 1/3 % of the same work in 8 days. They work together for 8 days. C alone completes the remaining work in 4 days. A and C together will complete the same work in:

    • A.33 1/8 days
    • B.12 days
    • C.9 days
    • D.10 days
    Show answer

    Answer: D. 10 days

    A's full work = 6/0.4 = 15 days. B's full work = 8/(1/3) = 24 days. In 8 days A+B = 8/15 + 8/24 = 64/120+40/120 = 104/120 = 13/15. Remaining 2/15 by C in 4 days → C alone = 30 days. A+C: 1/15+1/30 = 3/30 = 1/10 → 10 days.

  2. Q2.The length, breadth and height of a solid cuboidal box are in the ratio 7 : 5 : 3 and its total surface area is 11502 cm². Its breadth is:

    • A.27 cm
    • B.56 cm
    • C.81 cm
    • D.45 cm
    Show answer

    Answer: D. 45 cm

    TSA = 2(LB+BH+HL) = 2(35+15+21)x² = 142x² = 11502 → x² = 81 → x = 9. Breadth = 5×9 = 45 cm.

  3. Q3.The average age of 26 students in a class is 15 years. If teacher's age is included in it, then the average will increase by one. What is the teacher's age (in years)?

    • A.38
    • B.40
    • C.42
    • D.33
    Show answer

    Answer: C. 42

    Teacher's age = new avg + (n × increase) = 16 + 26 = 42.

  4. Q4.Find the greatest number of four digits which is divisible by 14, 30 and 42.

    • A.9780
    • B.9880
    • C.9870
    • D.9098
    Show answer

    Answer: C. 9870

    LCM(14,30,42) = 210. Greatest 4-digit multiple ≤ 9999: ⌊9999/210⌋ × 210 = 47 × 210 = 9870.

  5. Q5.A man sold 30 articles for ₹100 and gained 20%. The number of articles he bought for ₹100 was:

    • A.28
    • B.24
    • C.36
    • D.32
    Show answer

    Answer: C. 36

    SP per article = 100/30. CP per article = (100/30)/1.20 = 100/36. Articles for ₹100 = 100/(100/36) = 36.

  6. Q6.A money lender finds that due to a fall in the annual rate of interest from 10% to 8 3/4%, his year's income diminishes by ₹84.50. Find his capital.

    • A.₹7,660
    • B.₹6,940
    • C.₹6,760
    • D.₹7,460
    Show answer

    Answer: C. ₹6,760

    Difference in rate = 10 − 8.75 = 1.25%. So 1.25% of P = 84.50 → P = 84.50/0.0125 = ₹6,760.

  7. Q7.On selling an article for ₹984, Arun loses 18%. In order to gain 15%, he must sell it for:

    • A.₹1,440
    • B.₹1,132
    • C.₹1,265
    • D.₹1,380
    Show answer

    Answer: D. ₹1,380

    CP = 984/0.82 = 1200. To gain 15%: SP = 1200 × 1.15 = ₹1,380.

  8. Q8.Find the unknown value of x in the proportion (5x + 1) : 3 = (x + 3) : 7

    • A.1/8
    • B.1/14
    • C.1/17
    • D.1/16
    Show answer

    Answer: D. 1/16

    (5x+1)/3 = (x+3)/7 → 7(5x+1) = 3(x+3) → 35x+7 = 3x+9 → 32x = 2 → x = 1/16.

  9. Q9.Jagat Singh sold an article for ₹6,000 and incurred a loss. Had he sold it for ₹7,400, his profit would have been 2/3 of the amount of loss that he incurred. At what price should he sell it to gain 25% profit?

    • A.₹8,550
    • B.₹7,500
    • C.₹8,500
    • D.₹7,550
    Show answer

    Answer: A. ₹8,550

    Let CP=x, loss = x−6000. Profit at 7400 = 7400−x = (2/3)(x−6000). Solving: 3(7400−x) = 2(x−6000) → 22200−3x = 2x−12000 → 5x = 34200 → x = 6840. SP at 25% profit = 6840 × 1.25 = ₹8,550.

  10. Q10.The ratio of three numbers is 3 : 5 : 4 and the sum of their squares is 11250. Find the sum of the numbers.

    • A.180
    • B.150
    • C.225
    • D.165
    Show answer

    Answer: A. 180

    9x² + 25x² + 16x² = 50x² = 11250 → x² = 225 → x = 15. Sum = (3+5+4)×15 = 12×15 = 180.

  11. Q11.A person travels three equal distances at the speeds of 2 km/h, 3 km/h and 4 km/h and takes a total time of 52 minutes. The total distance is:

    • A.2.8 km
    • B.2.7 km
    • C.2.4 km
    • D.2.5 km
    Show answer

    Answer: C. 2.4 km

    Let each distance = d. d/2 + d/3 + d/4 = 52/60 → 13d/12 = 52/60 → d = 0.8 km. Total = 2.4 km.

  12. Q12.An object moves 15 m in 2.6 min and the next 26 km at a speed of 30 km/h. Find its average speed (in m/sec) for the whole movement.

    • A.8.59
    • B.3.76
    • C.7.94
    • D.2.92
    Show answer

    Answer: C. 7.94

    Per the worked solution, the average speed for the entire movement is approximately 7.94 m/s.

  13. Q13.Simplify the following. 30% of [{(820% of 40) ÷ 28}] % of 600

    • A.540
    • B.200
    • C.500
    • D.250
    Show answer

    Answer: A. 540

    Per the worked solution, the value evaluates to 540.

  14. Q14.At what rate of compound interest does a sum of money become 3.375-fold in 3 years, compounding annually?

    • A.50%
    • B.200%
    • C.100%
    • D.150%
    Show answer

    Answer: A. 50%

    (1 + R/100)³ = 3.375 → 1 + R/100 = 1.5 → R = 50%.

  15. Q15.A wholesaler has 1000 kg sugar, part of which he sells at 6% profit and the rest at 12% profit. His gain is 10% on the whole. The quantity sold at 6% profit is: (consider up to two decimals)

    • A.666.66 kg
    • B.336.33 kg
    • C.663.66 kg
    • D.333.33 kg
    Show answer

    Answer: D. 333.33 kg

    By alligation: 6% — 10% — 12%. Ratio = 2:4 = 1:2. So 1/3 of 1000 = 333.33 kg sold at 6% profit.

  16. Q16.Balvendra offers two successive discounts of 9% and 4% first and then he also provides a cash discount of ₹268 on the sale of a CCTV camera. If the marked price of the CCTV camera is ₹5,000, what is the final price of the CCTV camera for a customer?

    • A.₹4,000
    • B.₹4,368
    • C.₹4,100
    • D.₹4,636
    Show answer

    Answer: C. ₹4,100

    After 9% & 4%: 5000 × 0.91 × 0.96 = 4368. After ₹268 cash discount: 4368 − 268 = ₹4,100.

  17. Q17.Ram and Ramesh run two kilometres and Ram wins by 40 seconds. Ram and Naresh run two kilometres and Ram wins by 650 metres. When Ramesh and Naresh run the same distance, Ramesh wins by 25 seconds. Find the time taken by Ram to run two kilometres.

    • A.3 minutes, 15 seconds
    • B.2 minutes, 15 seconds
    • C.3 minutes, 35 seconds
    • D.2 minutes, 35 seconds
    Show answer

    Answer: B. 2 minutes, 15 seconds

    Per the worked solution, Ram takes 2 minutes 15 seconds to run 2 km.

  18. Q18.If the volume of a solid right circular cone is v cm³ and its height is h cm, then the radius of the cone is:

    • A.√(v/πh²)
    • B.√(3v/πh)
    • C.√(3v/πh²)
    • D.√(v/πh)
    Show answer

    Answer: B. √(3v/πh)

    V = (1/3)πr²h → r² = 3V/(πh) → r = √(3V/(πh)).

  19. Q19.Aman can do a piece of work in 78 days. Ram can do this work in 39 days. Aman started the work alone. After how many days should Ram join him, so that the work is finished in 39 days?

    • A.39/2 days
    • B.77/2 days
    • C.27/2 days
    • D.17/2 days
    Show answer

    Answer: A. 39/2 days

    Let Ram join after x days. Aman works 39 days alone first part, but actually: Aman 39 days = 39/78 = 1/2. Remaining 1/2 by both in (39−x) days at rate 1/78+1/39 = 3/78 = 1/26 → (39−x)/26 = 1/2 → x = 39/2.

  20. Q20.₹936 is divided among P, Q and R in the ratio 2 : 3 : 4 instead of 1/2 : 1/3 : 1/4 by mistake. The gain of R in the distribution is _____.

    • A.₹200
    • B.₹24
    • C.₹124
    • D.₹216
    Show answer

    Answer: A. ₹200

    Original ratio 1/2:1/3:1/4 = 6:4:3 (×12). Sum = 13. R's correct share = 936×3/13 = 216. Wrong ratio 2:3:4 sum=9. R's wrong share = 936×4/9 = 416. Gain = 416 − 216 = 200.

  21. Q21.The average weight of eight persons is 40 kg. If one person is removed, then the average weight becomes 38 kg. The weight of the removed person is:

    • A.38 kg
    • B.54 kg
    • C.33.25 kg
    • D.78 kg
    Show answer

    Answer: B. 54 kg

    Total of 8 = 320 kg. Total of 7 = 7×38 = 266. Removed = 320 − 266 = 54 kg.

  22. Q22.The cost price of an article is 64% of the marked price. Calculate the gain percentage after allowing a discount of 20%.

    • A.35%
    • B.25%
    • C.30%
    • D.20%
    Show answer

    Answer: B. 25%

    CP = 64. MP = 100. SP = 80 (after 20% discount). Gain% = (80−64)/64 × 100 = 25%.

  23. Q23.Atul alone can complete a work in 114 days. How many persons were required with the same efficiency as Atul to complete the same work in 19 days?

    • A.7
    • B.6
    • C.5
    • D.8
    Show answer

    Answer: B. 6

    Persons needed = 114/19 = 6.

  24. Q24.There is a cone with diameter 14 cm and height 12 cm. It is being filled with water at a rate of 4 cm³ in every 10 s. How long will it take to fill the cone? (Use π = 22/7)

    • A.616 s
    • B.1540 s
    • C.3080 s
    • D.6160 s
    Show answer

    Answer: B. 1540 s

    V = (1/3)π r² h = (1/3) × 22/7 × 49 × 12 = 616 cm³. Rate = 0.4 cm³/s. Time = 616/0.4 = 1540 s.

  25. Q25.The fourth proportional to 2 hours 40 minutes, 1 hours 20 minutes and 10 hours is:

    • A.4 hours
    • B.6 hours
    • C.5 hours
    • D.2 hours
    Show answer

    Answer: C. 5 hours

    Convert: 2h40m=160 min, 1h20m=80 min, 10h=600 min. Fourth proportional = (80×600)/160 = 300 min = 5 hours.

  26. Q26.The average weight of 34 persons is increased by 3 kg when one person weighing 90 kg is replaced by a new person. Weight of the new person is:

    • A.196 kg
    • B.202 kg
    • C.190 kg
    • D.192 kg
    Show answer

    Answer: D. 192 kg

    Weight of new = 90 + 34×3 = 90 + 102 = 192 kg.

  27. Q27.Find the difference between the digits of the greatest number that can exactly divide 144 and 216?

    • A.2
    • B.4
    • C.3
    • D.5
    Show answer

    Answer: D. 5

    HCF(144, 216) = 72. Difference of digits = 7 − 2 = 5.

  28. Q28.Two persons P and Q working together can do a piece of work in 36 days. Q alone can do it in 45 days. Q alone starts the work and leaves the work after 5 days. How many days will P take to complete the remaining work?

    • A.180
    • B.120
    • C.140
    • D.160
    Show answer

    Answer: D. 160

    1/P + 1/45 = 1/36 → 1/P = 1/180 → P = 180 days. Q in 5 days = 5/45 = 1/9. Remaining = 8/9. P takes 8/9 × 180 = 160 days.

  29. Q29.Divide ₹5,309 between A and B, so that the amount of A after 4 years is equal to the amount B after 6 years, the interest being compounded at 6% per annum, compounding annually.

    • A.₹2,809, ₹2,500
    • B.₹2,759, ₹2550
    • C.₹2,659, ₹2,650
    • D.₹2,709, ₹2,600
    Show answer

    Answer: A. ₹2,809, ₹2,500

    A(1.06)⁴ = B(1.06)⁶ → A/B = (1.06)² = 1.1236. So A:B = 1.1236:1. Solving with sum 5309 → A ≈ 2809, B ≈ 2500.

  30. Q30.If the third proportion to 3 and 27 is 'x', then what would be the HCF of 'x' and 27?

    • A.9
    • B.27
    • C.3
    • D.15
    Show answer

    Answer: B. 27

    Third proportion: x = 27²/3 = 243. HCF(243, 27) = 27.

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Frequently Asked Questions

How many SSC GD Constable Elementary Mathematics previous year questions are available?

450 Elementary Mathematics questions from past SSC GD Constable papers are available on AajExam, split into 45 practice sets. New questions are added as fresh papers are released.

Are the answers and explanations free?

Yes. Every question on this page shows its correct answer and explanation free of charge, and you do not need an account to read them. A free account only adds attempt tracking and performance analytics.

Do SSC GD Constable repeat questions from previous years?

Exact repeats do occur, but the more reliable pattern is conceptual: the same Elementary Mathematics sub-topics reappear cycle after cycle with reworded questions. That is why working through past questions raises your score more reliably than reading theory alone.

How should I use these questions in my SSC GD Constable preparation?

Attempt a set of ten cold, review every wrong and guessed question with its explanation, then drill the weak sub-topic on its topic page before moving on. Revisit the same set after a few days — your second-attempt accuracy is the honest measure of whether the concept stuck.

SSC GD Constable Elementary Mathematics practice sets

Each set is a timed 10-question drill drawn from the same question bank.

Related Elementary Mathematics topics